Suppose a parabola has an axis of symmetry at x = –7 , a maximum height of 4 and also passes through the point (–6, 0). Write the equation of the parabola in vertex form.
y = a(x+7)^2 + 4 If you substitute the given point for "x" and "y", you can solve for "a". Hint: "a" will be negative because the graph has a maximum value.
0 = a(-6 + 7)^2 + 4. Can you solve this for "a"?
I'm not actually sure, never did a word problem like this.
Well, you don't have to worry about the word problem nature of it at this point because I created the equations for you. Just work with those at this point.
Take my last equation and add -4 to each side. Simplify it and type it in this thread.
-4
You got it! Nice work, my friend!
Srry computer's running slow today
My computer always goes slow at Openstudy.
So I'm doing the equation like this? -4+0=(-6 + 7)^2+4+-4
Yes. When you typed in -4 before, I thought you were giving the answer for "a", because that is what it is equal to. a = -4. If you finished out the equation you started, that's what you would get for the answer.
Except you left out the "a"
I was giving the answer for "a". I was just wondering if that's what you wanted me to do afterwards.
I meant the equation, but you appear to know how to get that worked out, so you're fine! Good work, and it looks you are done!
Thanks so much then. (helpful as always lol)
you're welcome!
Join our real-time social learning platform and learn together with your friends!