Question

Needing help please -
why can't I use L'Hopitals rule for
lim x-> infinity x^1/x

Answer 1

\[x^{1/x}=e^\frac{\ln(x)}{x}\]

Answer 2

What does your equation look like? x^1/x?

Answer 3

@zordoloom yes

Answer 4

use what zarkon showed you. x^(1/x) = e^(ln(x)/x)
take the derivative of the ratio in the exponent(top and bottom)
e^((1/x)/1) = e^(1/x) at infinity e^(1/infinity) = e^0 = 1

Answer 5

Thanks!