Question

Help with logs?Cant use a calculator?:(

Evaluate, without using a calculator
5^(-2)

Answer 1

Oh wait i put the wrong one sowwy :( \[\log _{6}1\]

Answer 2

log(a)y = a^y

Answer 3

im a little confused.....would it be \[6^{1}\] than?

Answer 4

yes :)

Answer 5

ohh okay thankyou(: um may you help me with another one? Its a fraction?

Answer 6

yesm

Answer 7

thankyou!(: okay here it is\[\log _{6}\frac{ 1 }{ \sqrt[5]{36}}\] sorry it took a while to type it lol

Answer 8

i did the first one wrong it should be log(a)x = y and a^y =x

Answer 9

ohh... okay im confused now :(

Answer 10

the second one is a little out of my league lol you should open a new question with that second part!

Answer 11

lol alright but may you explain the first one pleaseee?(: <3

Answer 12

so log(a)x is the exponent to which the base a must be raised to give x

Answer 13

so to raise 6 by a power of zero will give an output of 1. any number raised to zero will give 1

Answer 14

x^0=1

Answer 15

2^0=1 and so on

Answer 16

so.... okay im not 100% sure but would the answer be 1?

Answer 17

Oh and another question (sorry lol) so do you always raise the little number by 0?

Answer 18

log(6)1=0
6^0=1

Answer 19

nope you 'exponentiate' the little number

Answer 20

log(6)1=0
since 6^0=1

Answer 21

okay okay...what does exponentiate mean im sorry for all these questions

Answer 22

The act of raising a quantity to a power :)

Answer 23

okay(: but im still confused :'(

Answer 24

they confuse me too hehe

Answer 25

log(a)x = y <=> a^y = x

Answer 26

just remember that a is your base, the base will always be the same for any log

Answer 27

any number raised to a power like a^x, a will be your base

Answer 28

imm off gluck

Answer 29

alright:/ thanks though <3