Use the derivitive to identify the open intervals on which the function is increasing or decreasing. f(x)=x^3/4 - 3x
first off take the derivative
Ok
Then what
Then check to see where the derivative is 0, and then check the derivatives domain
to get the critical numbers
If you get a critical number that isn't in the domain of the original function do not use it
Give me the critical numbers you get it is always smart to write on a test set f'(x) = 0
that is worth a mark or part of a mark at least because it shows you know what you are doing
Once you give me the critical numbers I will show you how to figure out in what intervals your function is increasing and decreasing
Ok is one of the numbers the sq root of 8/3?
ok you only got one critical number?
I'm studying for an exam while helping you so you will have to do most of the work if that is alright
I can show you the method of solving it though
That would be great if you could show me the method and its fine if you r studying
just say you only have one critical number Make a table like so: |dw:1352772038576:dw| Now plug in any number in the interal \[(-\infty, \sqrt{\frac{8}{3}})\] into f(x) and see if you get a positive or negative, the number doesn't matter just the sign Do the same with this interval \[(\sqrt{\frac{8}{3}},\infty)\] Tell me what your results are and I will show you how to fill out the table
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