A car traveling at 41 feet per second decelerates at a constant 7 feet per second squared. How many feet does the car travel before coming to a complete stop?

Question

anonymous · Answer

$$v ^{2} = u ^{2} + 2as$$

anonymous · Answer

v = initial velocity, u = final velocity, a = acceleration, s = displacement

anonymous · Answer

Can you help show me how to apply this? Thanks

anonymous · Answer

$$0 = 41^{2} + 2 (-7)(s)$$

anonymous · Answer

final velocity is when he stopped so it is 0. initial is 41. acceleration is opposite motion so its negative

anonymous · Answer

thanks :)

anonymous · Answer

$$v = u + at$$
$$v^{2} = u ^{2} + 2as$$
$$s = ut + \frac{ 1 }{ 2 }at ^{2}$$

anonymous · Answer

good equations to remember for kinematics questions

anonymous · Answer

Thanks!