Question

Find the equation in form f(x)=a(x-h)^2+k of the parabola that has vertex (-8,-11) at and passes through the point (-10,9)

Answer 1

f(x)=a(x+8)^2-11 passes the point (-10,9)
9=a[(-10)+8]^2-11
9+11=-2a
a=-10
Rewrite f(x)= -10(x+8)^2-11

Answer 2

umm isn't there a slight error in the value of a

9 + 11 = a(-2)^2

a = 5 so the equation is

y = 5(x + 8)^2 - 11

Answer 3

oops forgot the line

20 = 4a

so a = 5

Answer 4

and that make sense as (-8, -11) is the lowest point and (-10, 9) is above it

Answer 5

Oh yes, thank you @campbell_st!!