Question

2(x-6)<4 and 14+x+2≥20

Answer 1

distribute

Answer 2

then solve for x

Answer 3

I solved them separately

Answer 4

and then wrote the answer out showing both in one....

Answer 5

okay can i see

Answer 6

2(x-6) < 4
so multiply 2 to both x and -6
you get 2x-12 < 4

Answer 7

you have to solve for x on both equations

Answer 8

get x alone so add 12 to each side
2x < 16
and then divide each side by 2
you get x < 8

Answer 9

the second equation
so \[16+x \ge 20\]

Answer 10

subtract 16 from each side
\[x \ge 4\]

Answer 11

so what would 7x+14-4<4

Answer 12

\[4 \le x < 8\]

Answer 13

can u do the one on top

Answer 14

the 7x + 14 one?

Answer 15

yea

Answer 16

where did you get that from? is it a completely separate problem?

Answer 17

it is a differnt problem but im haveing troblue with it too and ur good at them so i thought you could help

Answer 18

7x+14-4<4 becomes
7x+10< 4 then
subtract 10 from each side, you get
7x< -6
divide each side by 7
x< -6/7

Answer 19

how would u graph this

Answer 20

oy! ok dashed line at (-6/7,0) and shade down (or under it)
does that sound right