Question

find derivative: f(x)= ln (3x+1)^4/(2x-1)^3

Answer 1

is ln for the entire fraction or just for (3x+1)^4?

Answer 2

\[\ln \frac{ (3x+1)^{4} }{(2x-1)^{3} } = \ln(3x+1)^{4}- \ln(2x-1)^{3}\]

Answer 3

yes

Answer 4

differentiate each one individually in the form of \[\frac{ f'(x) }{ f(x) }\]

Answer 5

and apply chain rule for each f'(x)

Answer 6

can you do it now?

Answer 7

im trying it now....thanks

Answer 8

\[\ln (3x+1)^4/\ln (2x-1)^3= \ln (3x+1)^4-\ln (2x-1)^3= 4*3\ln(3x+1)^3-2*2\ln (2x-1)^2 \]