Question

lim x->0 ln(secx) / tan^2(x), Can't use L'hospital Rule

Answer 1

=1/2 (lim x->0 ln(sec^2x) / tan^2(x)
=1/2 lim x->0 ln(1+tan^2(x)) / tan^2(x)
as x-->0 then tan^2(x)-->0
hence 1/2 lim x->0 ln(1+tan^2(x)) / tan^2(x)
=1/2 * 1=1/2

Answer 2

thanks alot, i got it!

Answer 3

welcome...