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if sin a = √5/5 and sin b = √10/10,where a and b are acute find Cos A
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is the problem: if \(\sin(\alpha)=\frac{\sqrt{5}}{5}\) find \(\cos(\alpha)\) ?
Yes
can u write the exact question
|dw:1352815707685:dw|
use cosA=sqrt(1-(sina)^2)=sqrt(1-5/25)=sqrt(4/5) =2/sqrt(5)
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there is a picture of an angle whose sine is \(\frac{\sqrt{5}}{5}\) what you need is the adjacent side, which you can find by pythagoras \[\sqrt{5}^2+a^2=5^5\] \[5+a^2=25\] \[a^2=20\] \[a=\sqrt{20}=2\sqrt{5}\]
the the ratio for cosine would be \[\cos(\alpha)=\frac{2\sqrt{5}}{5}\]
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