Question

Find a 2nd order equation such that c1e3t + c2e−t is its general solution.by Deriving

Answer 1

since it involves two arbitarary constant so u hav e to differentiate it twice
now y=c1e3t + c2e−t
differentiating we have y'=3c1e3t - c2e−t
again differentiating we have
y''=9c1e3t +c2e−t
thus eliminating c1 and c2 we have
y'' - 2y'-3y=0

Answer 2

@matricked thank you