Find the standard form of the equation of the parabola with a focus at (7, 0) and a directrix at x = -7.
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OpenStudy (anonymous):
.y =1/28 x2
x = 1/28 y2
-28y = x2
y2 = 14x
OpenStudy (anonymous):
x = 1/28 y2
OpenStudy (anonymous):
Find the standard form of the equation of the parabola with a focus at (0, 2) and a directrix at y = -2.
y2 = 2x
y = 1/2 x2
y2 = 8x
y =1/8 x2
@matricked
OpenStudy (anonymous):
y =1/8 x2
OpenStudy (anonymous):
Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0, 9).
y =1/36 x2
y =1/9 x2
y2 = 9x
y2 = 36x
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OpenStudy (anonymous):
@matricked
OpenStudy (anonymous):
y= =1/36 x2
OpenStudy (anonymous):
OpenStudy (anonymous):
@matricked
OpenStudy (anonymous):
i was offline and please don't specify me
as others have more knowledge to sort the problems
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OpenStudy (anonymous):
for Q5 its second option
OpenStudy (anonymous):
for Q6 let the eq of parabola be x^2=-k y
now substiute (14,-74) or (-14,-74) to find k and then use the eq for ur question