Question

Quadratic Equations:
A wire of length 200cm is cut into two parts and each part is bent to form a square. If the area of the larger square is 9 times that of the smaller square, find the perimeter of the larger square

Answer 1

let x cm be the length of the longer wire
length of shorter wire is thus (200-x)cm
\[(\frac{ x }{ 4 })^{2}= (\frac{ 200-x }{ 4 })^{2}\times 9\]
solve for x and you get the length of the longer wire which is in fact the perimeter of the larger square

Answer 2

do you understand the equation?

Answer 3

@irkiz I'm having trouble solving the equation

Answer 4

If the ratio of the areas is 9, then the ratio of the sides is 3.

Let x = the length of the smaller square, and 3x = the length of the larger square

4x + 4(3x) = 200
4x + 12x = 200
15x = 200
x = 40/3
3x = 40

The perimeter of the larger square is 160 cm.

Answer 5

ok @BelleFlower

Answer 6

Thank you so much! :) @Hares333