Question

please see attached

Answer 1

article 28 can somebody please talk me through????

Answer 2

They are just "detaching" the coefficients of each variable...

so like a^4 becomes just "1"... -3a^2b^2 becomes just "-3", and so on.

Whenever there is no exponent of a particular level, then it is written as if it had a coefficient of zero... so there is no a^3 term, but there is a 0 shown as a placeholder.

Answer 3

Each of the "columns" of numbers corresponds to a particular set of exponents.

So the very left-most column is for the a^4 term... then the next for a^3b, and so on toward the right.

Answer 4

what about the 0 in the second line. what place is that holding??

Answer 5

the second polynomial is (a^3 - 2ab^2 - 2b^3)

So there is no term with a^2 in it... in other words, the 2nd polynomial could be written as (1a^3 + 0a^2b - 2ab^2 - 2b^3)

Then the coefficients would be 1 +0 -2 -2 as shown in row # 2

Answer 6

ok i understand

Answer 7

thanks

Answer 8

That is an interesting but confusing method :)

Do you mind me asking what sort of text or "article" this is? It looks antique :)

Answer 9

synopsis of elementary results in pure mathematics
by g.s Carr

Answer 10

Thanks :)