Question

find the real solutions of the equation by graphing.
x^3-5x^2-12x=-36

(I dont have a graphing calculator)

Answer 1

you dont need one just graph it the old fashion way

Answer 2

I still dont know how to do it or anything

Answer 3

grab a piece of paper pick some points, plug into the equation you get your answer

Answer 4

should look like this

Answer 5

plug in the numbers where im so confused and ive been trying to solve it with a piece of paper and odnt get it

Answer 6

plug in numbers for x in the equation x^3-5x^2-12x=-36

Answer 7

a graph has x and y soooo how does that work

Answer 8

Let y = x^3-5x^2-12x+36
I suggest you find the following
(a) Turning points --> Set y' = 0 (differentiate y)
(b) Nature of turning points --> Plug in values for y'=0 into y'' (differentiate y') if y'' > 0 (min), if y''<0(max)
(c) Axial intercepts --> Plug in x=0 for y-intercepts & y = 0 for x-intercepts
Plot the turning points, making sure that you know its nature, and axial intercepts. Join them together

Answer 9

huh?

Answer 10

y = x^3-5x^2-12x+36
y' = 3x^2 - 10x - 12
y'' = 6x - 10

Answer 11

When x = 0, y = 36
When y = 0, x = -3 or 2 or 6
For turning points, let y' = 0
3x^2 - 10x - 12 = 0
\[x = \frac{-5±\sqrt{61}}{3}\]

Answer 12

ya pretty sure thats not what you need to do...

Answer 13

the answer is supposed to be 3 individual numbers

Answer 14

Im so confused