Solve by graphing. x2 + 2x – 3 = 0
Well if you have a calculator you could certainly graph it. But just factor it instead! No need for the quadratic formula here.
please help
I assume you have to graph this by hand, so get out a sheet of paper (if you haven't already) and start plotting points. I suggest using only integers as x since your answer will be an integer. The answer should become clear as you graph one point at a time
so what do you need help with? are you selecting one of those graphs?
yes
Can you eliminate any of them as being impossible?
Check your answer. Do the values of x beside the third graph make the equation true?
I don't think so
Oh I see the problem. The third graph is right, but the x-values beside it are wrong.
it would be -1,3 so is that right when I plugged that it for x I didn't get 0 but I might not be doing it right
no it would be 1,-3
so 1*1=1+ 2*-3=-6 - 3=0 but it doesn't it equals -9
none of them are going to be equal to 0 as far as I can tell
\[x ^{2}+2x-3=0\] test x=1,-1,3,-3\[1*1+2-3=3-3=0\]\[(-1*-1)-2-3=-1-3=-4\]\[3*3+6-3=12\]\[(-3*-3)-6-3=9-9=0\]
I'll help you with the factor :) (x+3)* (x-1) = 0. This means that x is 0 at -3, and at 1. Which plots have x being 0 at -3 and at 1? That leaves us graphs A & C. We know the function is positive so that leaves C as the correct answer.
You are so welcome.
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