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Mathematics 7 Online
OpenStudy (anonymous):

1/3-i-1/1+2i

OpenStudy (anonymous):

\[\frac{ 1 }{ 3-i }-\frac{ 1 }{ 1+2i }\]

OpenStudy (anonymous):

(1/10) + (1/2)i

OpenStudy (anonymous):

how did you get that

OpenStudy (anonymous):

@randomguyinternet plz respond

OpenStudy (anonymous):

is i an imaginary number?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

i got an asnwer but i just wunna check it..i got a diff one that the other guy

OpenStudy (anonymous):

so okay, it's easy

OpenStudy (anonymous):

1(1+2i) - 1(3-i)

OpenStudy (anonymous):

simplify that part first

OpenStudy (anonymous):

(1 / 3) - i - (1 / 1) + (2 * i) = -0.666666667 + i

OpenStudy (anonymous):

it shud be -2+3i

OpenStudy (anonymous):

now simplify the denominator of, (3-i)(1+2i)

OpenStudy (anonymous):

\[\frac{ 1+5i }{ 10 }\] is what i got :/

OpenStudy (anonymous):

no, it shud be \[\frac{ -2+3i }{ 5+5i }\]

OpenStudy (anonymous):

hmmm well you can't have a radical on bottom...and i is a radical number

OpenStudy (anonymous):

ok ok i got chu

OpenStudy (anonymous):

so multiply by 5-5i, both top and bottom

OpenStudy (anonymous):

(1+5i)/10 is correct

OpenStudy (anonymous):

so i was right lol

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