Find all solutions in the interval [0, 2π). cos x = sin x
I think unit circle would be useful here. I assume you are familiar with it? On the unit circle, the points are in the form (cos x, sin x). We want the points with the same x-value as y-value there.
The actual angles that we want, we just find the angle from the positive x-axis to the line containing that point and the origin. |dw:1352857780494:dw|
these are the options
@AccessDenied
Okay, but just so that we know how to find the answer. :) Here would be the unit circle, and the points we want lie on the line y = x. They happen to be (sqrt(2)/2, sqrt(2)/2) and (-sqrt(2)/2, -sqrt(2)/2). |dw:1352858018324:dw| We simply identify those two angles for our answer. Does that make sense?
Join our real-time social learning platform and learn together with your friends!