Question

how do you solve v^2+6v-59=0 by completing the square?

Answer 1

\[v^2+6v=59\]
\[(v+3)^2=59+9=68\]
\[v+3=\pm\sqrt{68}\]
\[v=-3\pm\sqrt{68}\]

Answer 2

or if you prefer, \(v=-3\pm2\sqrt{17}\)