Question

Can someone show me how to factor this step by step: 8x^2+18x+9

Answer 1

For a polynomial of the form ax^(2)+bx+c, find two factors of a*c (72) that add up to b (18).In this problem (3)/(2)*(3)/(4)=(9)/(8) (which is (c)/(a)) and (3)/(2)+(3)/(4)=(18)/(8) (which is ((b)/(a)) , so insert (3)/(2) as the right hand term of one factor and (3)/(4) as the right-hand term of the other factor.
(x+(3)/(2))(x+(3)/(4))

Answer 2

Remove the fraction by multiplying the first term of the factor by the denominator of the second term.
(2x+3)(4x+3)

Answer 3

thankx..

Answer 4

Hope it made sense.

Answer 5

here is a really simply method

for a quadratic ax^2 + bx + c = 0

multiply a and c in this question its 8 x 9 = 72

find the factors of 72 that add to 18.... 12 + 6

so then you have




remove common factors from each binomial



delete the common factor from the numerator and denominator... 8


leaves (2x + 3)(4x + 3) = 0

just solve now for x....


this method works all the time...