Question

An object is 10.0 mm from the objective of a certain compound microscope. The lenses are 300 mm apart, and the in-termediate image is 50.0 mm from the eyepiece. What overall magnification is produced by the instrument?

Answer 1

The total magnification will be:
\(M=\frac{250mm}{10mm} \times \frac{250mm}{50mm}=125times\)
The first being the objective magnification, second being eyepiece magnification.

Answer 2

So the answer is 125 times?

Answer 3

Yup! This applies to normal eyes of near point=25cm

Answer 4

Thank you so much!

Answer 5

You're welcome :)