Was trying to help someone with a highschool geometry problem. Now I am stuck myself
This ought to be interesting
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And what exactly were you asked to do with that?
given that \(m\angle Q=42^{\circ}\), and the line NQ bisects \(\angle MNP\), and the line PQ bisects \(\angle MPR\) Find \(m\angle M\)
not sure if it's the notation that is throwing me off?
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the internal angle sum of a triangle is 180° the internal angle sum of a quadrilateral is 360°
are the lines QM and RN parallel by any chance?
I wasn't sure, but I tried under that assumption.
oh the answer is 84 by the way. This isn't what I got
yup just tried again. is anyone actually trying this?
im trying
i dont think those lines could be parallel
that is what I figured as well. so I attempted by just assuming that N,P and R all lie on one line. But then I can't figure out if there is a solution.
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