Question

Given that 2.004 13 years ago

Answer 1

10101 in binary? then 210 shouldn't be binary....

Answer 2

( 101101)base2=( 45)decimal binary no always power of 2 therefore 2power 6= 64
hence 6 digit req..

Answer 3

brilliant!

Answer 4

it is 101^101

Answer 5

@ParthKohli

Answer 6

help!

Answer 7

Well, find out \(\log_{10} 101^{101}\)

Answer 8

then

Answer 9

That's it.

Answer 10

that is the no. of digits?

Answer 11

Yes

Answer 12

how log can help calculate no. of digits?

Answer 13

Yes, it does. Try it!

Answer 14

202 is incorrect

Answer 15

You also have to consider the assumptions given in your question.

Answer 16

what else is given?

Answer 17

Actually, you have to find \(1 + \log_{10} 101^{101}\). Don't write in the answer, let me check first.

Answer 18

ok

Answer 19

You can do something else while I check. Thanks :-)

Answer 20

ok

Answer 21

203.

Answer 22

And so I was correct :-)

Answer 23

why add 1?

Answer 24

Because the number of digits in \(100\) is not \(\log_{10} 100\), but it's \(1+\log_{10}100\)

Answer 25

ok thanks

Answer 26

can it be used for counting digits in any expansion?

Answer 27

Expansion? You mean number base?

Answer 28

like this type of question

Answer 29

Yes.

Answer 30

ok thanks