Question

write down two sets of a and b such that log(ab)=(log a)(log b).

Answer 1

@hartnn @Calculator @amistre64

Answer 2

log(ab)=log(a) +log(b)

Answer 3

and then?

Answer 4

that is all, remember this log base 10

Answer 5

i can think of one.... (1,1)

Answer 6

errr...well...
examples?

Answer 7

yes log(ab) is equal to log a + log b

Answer 8

log(ab)=(log a)(log b)....

Answer 9

not that...(log a)(log b)=log (b)^log b

Answer 10

why (log a)(log b)=log (b)^log b????????

Answer 11

I mean= log (b)^log (a)

Answer 12

ok...and ?

Answer 13

\[\log_{10}(ab) = \log_{10}(a) + \log_{10}(b)\]

Answer 14

but we need to write down two sets, that means examples...

Answer 15

trial and error?

Answer 16

\[\log_{10}(a) = x \]
is equal to
\[10^{x} = a\]

Answer 17

you want
log(ab)=(log a)(log b)

by properties of logs
log(ab)=log(a) +log(b)

so you want
(log a)(log b) = log(a)+log(b)

let A= log a B= log B
AB= A+B
or
A(B-1)= B
A= B/(B-1)

now pick a number for B:
example B=0 --> A=0
log a= 0 --> a=1, log B=0 --> b=1

or
B=2
A= 2
log a= 2--> a= 100, log b= 2 ---> b= 100

and so on

Answer 18

o.o

Answer 19

\[\log_{10}(b) = y\]
is equal to
\[10^{y} = b \]

Answer 20

@gerryliyana I know...

Answer 21

ok @kryton1212 nice

Answer 22

I know now. Thanks.

Answer 23

ur welcome pretty :D

Answer 24

may I ask another question in this post :P?

Answer 25

of course.., please :D

Answer 26

Construct a logarithmic function such that f(5)=2.

Answer 27

do you get to pick the base?

Answer 28

if so you can use
\[\log_{\sqrt{5}}(x)\]

Answer 29

then
\[\log_{\sqrt{5}}(5)=2\] since \(\sqrt{5}^2=5\)

Answer 30

and then?