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Mathematics 17 Online
OpenStudy (anonymous):

Factor 25x^2+60x+36

OpenStudy (anonymous):

(5X+6)^2

OpenStudy (anonymous):

how did u get that?

OpenStudy (anonymous):

Start by (5x + n)(5x + n). "n" is the same for both factors. It is a perfect square.

OpenStudy (anonymous):

You start by doing either (25x + ?)(x + ?) or (5x + ?)(5x + ?) and come to the conclusion that the second one is more workable.

OpenStudy (anonymous):

break down 25 and 36 into there factors 25= 1 and 25 or 5 and 5 36= 1 and 36, 2 and 18, 3 and 12, 9 and 4 and 6 and 6 now this is what you need to fill in (_x -_)(_x-_) to get the answer (its minus because of the negative sixty) soooo 1 and 25 don't seem plausible so five and five are the factors you probably want to use, so fill in (5x-_)(5x-_) now what multiplied by five (factors of 36) will equal sixty when added. you can try each, or if you know it you can figure it out... so running through some .... three times five is fifteen plus 12 times five is sixty and that is more than the middle number. five times six is thirty, five time six is thirty, added together its sixty and that fits the equation. so (5x-6)^2 is the answer because both the parenthesis are the same. then solve for x. Man that probably didnt' help.

OpenStudy (anonymous):

oh ok! i get it now

OpenStudy (anonymous):

Good luck in all of your studies!

OpenStudy (anonymous):

but what do I do if i have something like this 9x^2+25x-54 so would i make the 9 a 3 ??? or do i multiply 9 and -54..

OpenStudy (anonymous):

You can again start with either (3x + ? )(3x - ?) or go with (9x ?)(x ?). Here, with the second choice, we can't assign the signs just yet.

OpenStudy (anonymous):

So, we exhaust the first possibility first.

OpenStudy (anonymous):

oh ok!

OpenStudy (anonymous):

Actually, I go right to the quadratic fromula most of the time. In this case, it's good to go to the quadratic formula, because this one does not factor nicely.

OpenStudy (anonymous):

alright!

OpenStudy (anonymous):

So, for this last one, you would otherwise just go nuts if you tried to factor it !

OpenStudy (anonymous):

So, for this last one, don't factor it, just go to the quadratic formula.

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