Question

x=(the following equation is all UNDER a radical) 2x+24

Answer 1

You need to get rid of the radical first eg. x = \[\sqrt{x+3}\] get rid of the root (square root) by squaring both sides of the equation: \[x^{2} = (\sqrt{x+2})^{2}\]

Answer 2

you are then left with \[x^{2} = x+2\]

Answer 3

After this step put all the terms on the same side : \[x^{2}-x-2=0\]
Then solve for x by factoring or using the quadratic equation:
by factoring: (x-2)(x+1)=0
Then using the zero factor property (a)(b)=0:
(x-2)=0 and (x+1)=0.
Solve for x in each term:
x=2 and x=-1