Write a function with the given characteristics? (details inside)
A polynomial with rational coefficients having roots 3, 3, and 3-i
does this mean 3 is a root twice?
\[(x-3)^2(x-(3+i))(x-(3-i))\]
yes, and i'm confused because i need to find the original equation (for example, something like x^3 + x^2 + x + k)
Just multiply the factors that satellite73 gave in is response above.
but then won't i end up with 3i as part of the polynomial?
1. multiply (x-3)*(x-3) you should get: (x^2-6x+9) - ans 2. multiply (x-3-i)(x-3+i) You should get: x^2 - 3x +ix-3x+9-3i-ix+3i-i^2 (remember i^2 = -1) NOTE: ix and -ix cancels, -3i and 3i cancels. You should have left: (x^2-6x+10) - ans 3. multiply the ans in part1 by the answer in part2 (x^2-6x+9)(x^2-6x+10)=(x^4-6x^3+10x^2-6x^3+36x^2-60x+9x^2-54x+90) =(x^4-12x^3+55x^2-114x+90) (simplify by combining like terms) Answer: (x^4-12x^3+55x^2-114x+90)
Thank you so much!
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