Question

x^2+6x+8
polynomial expression.

Answer 1

what's the question?

Answer 2

example (x+2)(x+5)

Answer 3

oh, so you need to factor the equation?

Answer 4

yes

Answer 5

okay well here's how:
x^2+6x+8=0
first you need to find the two factors of eight that will add up to 6
(in this case 4 and 2)
(x+2)(x+4) = x^2+6x+8

Answer 6

y=x^(2)+6x+8

To find the roots)/(zeros of the function, set the function equal to 0 and solve.
0=x^(2)+6x+8

Since x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
x^(2)+6x+8=0

In this problem 4*2=8 and 4+2=6, so insert 4 as the right hand term of one factor and 2 as the right-hand term of the other factor.
(x+4)(x+2)=0

Set each of the factors of the left-hand side of the equation equal to 0.
x+4=0_x+2=0

Since 4 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 4 from both sides.
x=-4_x+2=0

Set each of the factors of the left-hand side of the equation equal to 0.
x=-4_x+2=0

Since 2 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2 from both sides.
x=-4_x=-2

The complete solution is the set of the individual solutions. The multiplicity of a root is the number of times the root appears. For example, a factor of (x+5)^(3) would have a root at x=-5 with multiplicity of 3.
x=-4,-2