Question

Explain how you use the pattern of imaginary numbers to determine what i^18 equals

Answer 1

1

Answer 2

jus 1??? how would i explain that??

Answer 3

\[i = \sqrt{-1}\]
\[i^8 = \sqrt{(-1)^{2}(-1)^{2}(-1)^{2}} = 1\]

Answer 4

Remember that i is the square root of -1.
Now look at this sequence: i=sqrt(-1), i^2=-1, i^3=-sqrt(-1), i^4=1
Now from i^5 we are just multiplying 1 by i, and that makes us return to the begining of the cycle, so 18 is not a multiple of four, but 16 is, and if we look at the begining of the cycle from 16, we need to go two steps ahead, and we see that i^18=i^2=-1
@EarthCitizen thats wrong, you did for 8, its 18.

Answer 5

yh, I thought i saw 8 my bad @ivanmlerner is correct

Answer 6

anyways @Swageraid32 u get the gist boss ?