Given: Base ∡BAC and ∡ACB are congruent. Prove: ∆ABC is an isosceles triangle. When completed, the following paragraph proves that line ab is congruent to line bc making ∆ABC an isosceles triangle. Construct a perpendicular bisector from point B to line ac . Label the point of intersection between this perpendicular bisector and line ac as point D. m∡BDA and m∡BDC is 90° by the definition of a perpendicular bisector. ∡BDA is congruent to ∡BDC by the _______1________. line ad is congruent line dc to by _______2________. ∆BAD is congruent to ∆BCD by the Angle-Side-Angle (ASA)
a. 1. the definition of congruent angles 2. Angle-Side-Angle (ASA) Postulate b. 1. the definition of congruent angles 2. the definition of a perpendicular bisector c. 1. Angle-Side-Angle (ASA) Postulate 2. the definition of a perpendicular bisector d. 1. Angle-Side-Angle (ASA) Postulate 2. corresponding parts of congruent triangles are congruent (CPCTC)
i dont think it is A... so that leaves me with B Cand D. any help? @SmoothMath
The CPCTC is the only part that looks correct to me. Since you're proving two triangles are congruent, and then showing one part of those triangles is congruent.
The correct answers are: 1) the two triangles are congruent by "side-angle-side" 2) AB is congruent to BC by "CORRESPONDING parts of congruent triangles are congruent (CPCTC)"
idk that really confusing but i think i might be right
Okay, thank you for your help(:
no problem...
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