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log64^8
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\[\log _{64}8\]
so 8*2= 64
so its =-2 @JakeV8
why -2? Why not 2?
oh, wait... I read it backwards at first.
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What exponent would you have to raise 64 to get 8?
2
no, that would be 64 squared... 64^2 = 4096
oh im so lost
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You were on the right track. 8 is the square root of 64, right? Have you ever seen a square root expressed as an exponent?
yeah
\[\sqrt{64} = 64^{\frac{ 1 }{ 2 } }\]
The answer to \[\log _{64}8\] is the exponent that you would have to raise 64 to to get 8.
oh how did you 1/2
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I have to refer to the log definition all the time... here it is again: \[y = b ^{x} <------> \log _{b}y = x\]
I didn't understand your last comment... was it "how did I get 1/2 ?"
or wrap this math around my head. lol
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