Question

ok just want to see if i got this right

Answer 1

\[\sqrt[3]{3x-1}=5\] i got \[\frac{ 42 }{ 3 }\]

Answer 2

nope

Answer 3

cube both sides

Answer 4

\[(\sqrt[3]{3x-1})_{}^{3} = 5^{3}\]

Answer 5

\[\sqrt[3]{3x-1}=125\]
-1=126
3x=126
\[\frac{ 126 }{ 3 }\]

Answer 6

which is 42

Answer 7

yup you are right now

Answer 8

oh ok so its not 42 over 3 its just 42