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Mathematics 22 Online
OpenStudy (anonymous):

Can someone help? I'm working on a Geometry proof. I have the first three steps, but I don't know where to go from there.

OpenStudy (anonymous):

In the following figure, the small circle and the large circle have the same center O. Chord AB is tangent to the smaller circle at C. Prove that the area between the large and small circles is the same as the area of the circle that has AB as a diameter. |dw:1352948427958:dw|

OpenStudy (anonymous):

This is what I have so far, but I don't think its right. Statements: Reasons: 1. O is the center of both 1. Given a small and large circle. Chord AB is tangent to C. 2. Construct line CO 2. Construction of radius of smaller circle. 3. Angle OCB is 90 degrees 3. Intersecting Tangent and radius (Theorem 7.11)

OpenStudy (anonymous):

3.reason...it forms right angle

OpenStudy (anonymous):

but all of your answers are correct

OpenStudy (anonymous):

Okay. But now I have no idea where to go from Step 3.

OpenStudy (anonymous):

OC = radius of small circle area of small circle = pi(OC^2) AC^2 + OC^2 = AO^2 AO = sqrt(AC^2 + OC^2) = radius of larger circle area of lager circle = pi(AO^2) = pi(AC^2 + OC^2) area between circle = area of big - area of small pi(AC^2 + OC^2) - pi(OC^2) = pi(AC^2) area of of circle with diameter ab = pi(AC^2) both the same

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