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Mathematics 7 Online
OpenStudy (anonymous):

find centroid of the region bounded by y=ln(x) the axis and x=e

OpenStudy (anonymous):

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OpenStudy (tkhunny):

First, you'll need the total area. What do you get?

OpenStudy (anonymous):

you have to do double integral to find mass right?

OpenStudy (anonymous):

so it will be (e-1)p?

OpenStudy (tkhunny):

Right, I assumed the very common uniform density. Sorry abuot that. "e-1"? No. How did you get that?

OpenStudy (anonymous):

im confused about setting out the integrals limits

OpenStudy (anonymous):

is it e(loge-1)

OpenStudy (anonymous):

\[\int\limits_{1}^{e}\int\limits_{0}^{\ln(x)}p dydx\]

OpenStudy (tkhunny):

\[\int\ln(x)\;dx = x\ln(x) - x + C\] (e*ln(e) - e) - (1*ln(1) - 1) = e*ln(e) - e - 0 + 1 = e(1) - e + 1 = e-e+1 = 1

OpenStudy (anonymous):

what is that? is that a mass?

OpenStudy (tkhunny):

\[\int_{1}^{e}\int_{0}^{ln(x)}\rho\;dy\;dx = \rho\]

OpenStudy (anonymous):

for the center mass the integral will be the same?

OpenStudy (tkhunny):

It's not a matter of guesing or whether we can predict it or how we feel about it. It's just how it works out on this one,

OpenStudy (anonymous):

\[\int\limits_{1}^{e}\int\limits_{0}^{\ln(x)}xpdydx\]

OpenStudy (anonymous):

just wanna know if this is the integration

OpenStudy (tkhunny):

Yes, that is one of them.

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