Question

Homework11 and LAB11answers......!

Answer 1

p1: L=0.65mH, RL=4 ohms, RC=490Kohms

1.)1/(RC*C) + RL/L
2.)92.236 (f=650khz)
3.)4.5
4.)22 (f=1330khz)
5.)16

p2:

1.)vm*0.1=0.01
2.)Cs/Rp=2.55
3.)Cs/Rp=2.55
4.)0.8

p3:

1.)C
2.)R
3.)L
4.)4
5.)L
6.)1000
7.)1
8.)16

Answer 2

LAB11:

1.)0.001592
2.)1.592e-7
3.)0.0356
4.)10

Answer 3

hi rvamsi, what is the eq. for H11P2 part (4) ...

Answer 4

no wonder why i was having trouble with the ifrst part of lab 11. Those guys are idiots. They said wo=10k which means 2*pi*f=10k.. they actually meant that fresonance=10k, THEREFORE wo=62.8k

Answer 5

Q1 and Q2 equations please my frequency is different

Answer 6

hi vamsi can u please say me the equation for finding capacitor in H11Q1

Answer 7

for H11P1
que1
use C=1/(L*((2*3.14*f)^2))

Answer 8

Hello there fellas, can't get H11P2 - part 4 and 5. can anybody sort this for me? I have f=1150 kHz. Appreciate it

Answer 9

problem 2 or problem 1?

Answer 10

Oops, sorry, P1 it is. part 4 and 5

Answer 11

At f = 1150 kHz, finding capacitance and badwidth

Answer 12

ans for 4=29.496
ans for 5=75.343

Answer 13

please select best response if it is correct if not pls respond i will try again

Answer 14

Ahh, thank you Mr. Siva, part 4 is correct but nit agreeing on 5. the one that asks for bandwidth. Do you know what could be wrong? Thank you sir

Answer 15

oops small mistake ans for 5 is 11.991

Answer 16

Grrreeeat! Thank you very much. You have helped me ace it. :)

Answer 17

No mention
if u are done with H12 P3 please give me the formula or equations for that

Answer 18

Plz can you tell me the formula to calculate bandwidth for part 3 of HW 11

Answer 19

and I cant understand how to find Cp..

Answer 20

hey what is the need of BW in P3

Answer 21

pls give me the Q no

Answer 22

BW for part 3 of H11P1...but I got it...I wasn't dividing the answer with 2*pie so....but now I am stuck in H11P2 last part

Answer 23

P1 2&3 f= 1010 4&5 1030 khz

Answer 24

b) (thats the formula = 1/(2*pi*f)^(2)*L)
c) (thats the formula = 1/(RC*C) + RL/L)
d) (thats the formula = 1/(2*pi*f)^(2)*L)
e) c) (thats the formula = 1/(RC*C) + RL/L)

H11P2
d) 0.1*VM(t)

Answer 25

Click best if helped
I got 38.2 and for b and d of h11p2. Cant get right answer for c and e Plz Help
Rc = 490k, RL = 4 L = .65mH f= 1010 and 1030 rsp.

Answer 26

Coolampio, I try to use the formula 1/(RC*C) + RL/L) in c) and e), but I've got a wrong answer. my f=740kHz & 1660kHz. I've got capacitances 71pF & 14pF respectively. But in questions c & e I've got 35kHz and 151kHz, it's wrong.

Answer 27

For d, I got 36.7 forgot to mention up
having pblem with same ones my self

Answer 28

I find it! For c) & e) parts of h11p1 we need divide the formula: "1/(RC*C) + RL/L" by 2pi.

Answer 29

What is the bandwidth, in 770 kHz, of the tank at kHz?

Answer 30

Mahmoudmosad, your bandwidth is 5.9kHz