Question

find the antiderivative of (3x+10)(3x-10)

Answer 1

we havent learned rules of multiplication when it comes to antiderivatives yet...so not sure how to handle it

Answer 2

you have to expand it then you do it like the other ones. \[9x^2-100\]

Answer 3

\[\frac{ 9x^3 }{ 3 }+100x +C\]

Answer 4

oh ok
so the antiderivative is 3x^3-100x

Answer 5

ya plus the constant

Answer 6

thx!

Answer 7

-100 not +100 sorry

Answer 8

i have another question about antiderivatives if you could help please :)

Answer 9

sure

Answer 10

the antiderivative of (x^.5+.5x^-.5)2
(the square root of x plus half times square root of x (in denominator))squared

Answer 11

because if i do it the other way you did before (add the the expoenent) and divide by it.....it doesnt work because when you take the derivative you gotta take it of the inside function as well

Answer 12

how bout if you distribute the ^2 ?

Answer 13

x^2.5+.5x^1.5

Answer 14

then you can do it like normal

Answer 15

oooo ok thx

Answer 16

wouldnt you multiply the 2 not add it .....so it would be x+.5x^-1

Answer 17

nah think of 10^2 * 10^2 = 100*100=10,000 = 10^4

Answer 18

or 10^4* 10^2 = 10,000 * 100 = 1,000,000 = 10^6

Answer 19

but thats because they have the same base.....(a^x)^y = a^xy not a^(x+y)

Answer 20

x^2 =(x)^2 = (x)x it's all the same

Answer 21

pull out your calculator and try some examples just plug in any number for x

Answer 22

3x^3-100x+constant