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Physics 10 Online
OpenStudy (anonymous):

Read the passage carefully and answer the questions: A source of sound is placed at one end of an iron bar two kilometer long and two sounds are heard at the other end at an interval of 5.6 seconds. If the velocity of sounds in air is 330 m/s. Q1) The time taken by sound to travel 2 km in iron is- a) 0.46 s b) 0.16 s c) 2.26 s d)3.36 s Q2) Velocity of sound in iron is - a) 2348 m/s b) 4348 m/s c)1300 m/s d) 5223 m/s

OpenStudy (anonymous):

@Zarkon @Agent_Sniffles @AccessDenied @jazy @TranceNova @hba plz help

OpenStudy (anonymous):

@Jonask @zordoloom

OpenStudy (anonymous):

@thinker1

OpenStudy (anonymous):

VELOCITY O0F SOUND IN AIR=330M/S THUS TIME TAKEN BY SOUND TO TRAVEL 2 KM IS (2000/330)S=6.06STHUS SOUIND TRAVEL IN IRON IN (6.06-5.6)S=0.46S

OpenStudy (anonymous):

TYHUS VELOCITY OF SOUND IN IRON IS (2000/0.46)M/S=4347.8M/S

OpenStudy (anonymous):

DO U UNDERSTTAND @Hares333

OpenStudy (anonymous):

why you subtract 6.06-5.6??

OpenStudy (anonymous):

BECAUSE THERE IS A TIME LAG OF 5.6 S IN BETWEEN THE SOUND RECIEVED DIRECT THROUGH AIR AND ONE RECIVED THROUGH IRON.SINCE SOUND TRAVELS FASTER IN METAL THAN AIR I HAVE SUBTARCTED THE TIME LAG FROM THE TIME TAKEN BY SOUND IN AIR TO KNOW TIME TAKEN TONTRAVELIN IRON .IF IT HAD BEEN A MEDIUM LESS DENSER THAN AIR INSTEAD OF ROD I WOULD HAVE ADDED WOUL

OpenStudy (anonymous):

IS IT OK?

OpenStudy (anonymous):

yaa..thnx...

OpenStudy (anonymous):

U R WELCOME

OpenStudy (anonymous):

TYHUS VELOCITY OF SOUND IN IRON IS (2000/0.46)M/S=4347.8M/S this line????

OpenStudy (anonymous):

@thinker1

OpenStudy (anonymous):

VELOCITY OF SOUND IS =(DISTANCE TRAVERSED / TIME TAKEN)=(2000M/.46S)

OpenStudy (anonymous):

ohkkk thnx again!!!

OpenStudy (anonymous):

UR WELCOME AGAIN

OpenStudy (anonymous):

can you help me in chemistry?

OpenStudy (anonymous):

@thinker1

OpenStudy (anonymous):

can you help me???

OpenStudy (anonymous):

LET ME SEE WHAT IT IS

OpenStudy (anonymous):

Water gas is an equimolar mixture of hydrogen and carbon monoxide. If 250 litres of water is burnt in air, calculate the following assuming both reactants and products are at same temperature and pressure. \[2CO+O_2->2CO_2 ; 2H_2+O_2->2H_2O\] Q1) Volume of carbon Dioxide produced- a) 125 l b) 62.5 l c) 250 l d) 500 l Q2) Volume of steam produced - a) 62.5 l b) 250 l c) 125 l d) 375 l

OpenStudy (anonymous):

@thinker1

OpenStudy (anonymous):

IT IS STRANGE HOW CAN WATER BE BURNT (AS WRITTEN IN UR QUESTION)

OpenStudy (anonymous):

@Hares333

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