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Find the limit.
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At this point its infinity. ;)
\[\lim_{x \rightarrow 0} (3x+2+(1/x^2))\]
thats a interesting one :p
I would multiply the whole function by x^2 to get it out of the denomenator then plug 0 in for x.
are you allowed to do this?
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i don't think you can
actually no. Limit does not exist. sorry.
L[x:0,3x+2+((1)/(x^(2)))]
its infinity right?
wow batman is not even here, but we're here seating and figuring out someones problem
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;)
I graphed it, looks like it goes to positive infinity.
Okay i checked with calculator function and both forms confirm that it goes to infinity.
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