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Mathematics 6 Online
OpenStudy (anonymous):

differentiate 1 over 2^t

OpenStudy (anonymous):

what? how can I do that..... there all part of one fraction

OpenStudy (anonymous):

the answer is -2^(-t) ln 2. but i want to know how to get that answer?

OpenStudy (anonymous):

I don't really understand about that..

OpenStudy (anonymous):

first take log log 2^-t= -t (ln2)

OpenStudy (anonymous):

wwhats on other side ?

OpenStudy (anonymous):

it same when we differentiate the exponent.. for example: e^-x solution: e^-x.-1.ln e = e^x... for this problem u should be let exponent to be 2.. so the solution: 2^-t.-1.ln 2 =-2^-t ln 2

OpenStudy (anonymous):

did u get it?

OpenStudy (anonymous):

not so.. pls explain further tq..

OpenStudy (anonymous):

Ahh...I know it...thank you @sha0403

OpenStudy (anonymous):

how there is ln 2? and not ln 2^t?

OpenStudy (anonymous):

because it known as formula.. have u see my solution of the exponent? we must let e to be 2 in 2^-t

OpenStudy (anonymous):

ohh yes. now i can recall back. TQVM sha :)

OpenStudy (anonymous):

welcome :)

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