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Mathematics 16 Online
OpenStudy (anonymous):

(5x-1)^2=4/25

OpenStudy (anonymous):

5x-1=2/5 5x=7/5 x=7/25

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

shouldn't it be: \(\large 5x-1=\pm \frac{2}{5} \) ???

OpenStudy (anonymous):

Yes. we should include pm... ie plus minus..

OpenStudy (anonymous):

ok so can you explain the step by step after sq rooting that you get 3/25 and 7/25 as the answer that is where i get lost

OpenStudy (anonymous):

Take the square root both the sides and tell me what are you getting?

OpenStudy (anonymous):

i'm getting 5x-1= 2/5, but what do i do after that?

OpenStudy (anonymous):

b/c there are 2 answers 3/25 and 7/25

OpenStudy (anonymous):

Yes, there will be two answers for this...

OpenStudy (anonymous):

Actually, when we take square root of any number we consider plus minus sign with it : Like : \[(5x-1)^2 = \frac{4}{25}\] \[\implies 5x - 1 = \pm \frac{2}{5}\]

OpenStudy (anonymous):

Now, firstly you will consider + sign with 2/5 and then in second case you will consider - sign with 2/5 Solve by using + 2/5 first..

OpenStudy (anonymous):

For Plus Case : \[5x - 1 = \frac{2}{5}\] Solve this for x..

OpenStudy (anonymous):

Now Minus Case : \[5x - 1 = -\frac{2}{5}\] And now find x in this case..

OpenStudy (anonymous):

ok so then do i divided each side by 5?

OpenStudy (anonymous):

Firstly add 1 both the sides...

OpenStudy (anonymous):

\[5x - 1 = \frac{2}{5}\] Add 1 to both the sides and tell me what you got?

OpenStudy (anonymous):

ok so then i have 5x= 1+2/5 = 5x=3/5

OpenStudy (anonymous):

How you got 3/5 ??

OpenStudy (anonymous):

\[1 + \frac{2}{5} = ?\]

OpenStudy (anonymous):

i just added the 1 to the 2

OpenStudy (anonymous):

No, you cannot add 1 to the fraction directly.. Do you know about LCM or LCD ??

OpenStudy (anonymous):

oh yes

OpenStudy (anonymous):

Then use that...

OpenStudy (anonymous):

ok so the lcd would be 5 making the fraction 5/5 correct?

OpenStudy (anonymous):

Correct..

OpenStudy (anonymous):

ok so adding 5/5 to 2/5 gives you 7/10 am i wrong there

OpenStudy (anonymous):

See, you, in LCD, never add denominator, the denominator remains the same.. Just add or subtract the numerator...

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

\[\frac{5}{5} + \frac{2}{5} = \frac{5 + 2}{5} = \frac{7}{5}\]

OpenStudy (anonymous):

thank you now i see where my issues were :)

OpenStudy (anonymous):

So, now you got : \[5x = \frac{7}{5}\] Now divide by 5 here to get x..

OpenStudy (anonymous):

you getr 7/25

OpenStudy (anonymous):

Yes...

OpenStudy (anonymous):

Now : \[5x - 1 = -\frac{2}{5}\] Add 1 to both the sides...

OpenStudy (anonymous):

0.28,0.12

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