Calculus1
8 Online
OpenStudy (anonymous):
if F(x)=tanx, then fprime(pi/6)=
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OpenStudy (anonymous):
Have you differentiated F(x) and then sub'ed \(\frac{\pi}{6}\) into it?
OpenStudy (anonymous):
Do you know the derivative of tan(x) ??
OpenStudy (anonymous):
i kno the differvative is secxtanx
but i dont know where to go frm there :/
OpenStudy (anonymous):
Yes, than just replace x by pi/6..
OpenStudy (anonymous):
(2\[\sqrt{3}\]/3 and \[\sqrt{3}\]/3
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OpenStudy (anonymous):
\[F'(\frac{\pi}{6}) = \sec(\frac{\pi}{6}) \cdot \tan(\frac{\pi}{6})\]
OpenStudy (anonymous):
igot tht part
OpenStudy (anonymous):
What is the value of :
\[\sec (\frac{\pi}{6})\]
OpenStudy (anonymous):
2root3/3
OpenStudy (anonymous):
Yes and what is for tan(pi/6) = ??
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OpenStudy (anonymous):
root3/3
OpenStudy (anonymous):
Wait, derivative of tan(x) isn't it sec^2(x) ??
OpenStudy (anonymous):
its not ?
OpenStudy (anonymous):
\[\frac{d}{dx} \tan(x) = \sec^2(x)\]
OpenStudy (anonymous):
thts y im getting the wrong answer
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OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
You were doing the derivative of sec(x)..
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
\[\frac{d}{dx}\sec(x) = \sec(x) \cdot \tan(x)\]
It is okay and sorry from my side too, I also got confused..
And you are welcome dear..
OpenStudy (anonymous):
ok idk how to combine the 2 radicals
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OpenStudy (anonymous):
Where ??
OpenStudy (anonymous):
sec^2
OpenStudy (anonymous):
\[F'(\frac{\pi}{6}) = \sec^2(\frac{\pi}{6})\]
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
|dw:1352970940060:dw|
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OpenStudy (anonymous):
\[\implies \frac{2 \sqrt{3}}{3} \times \frac{2\sqrt{3}}{3} \implies ??\]
OpenStudy (anonymous):
This is simple multiplication and division now...
OpenStudy (anonymous):
i know but im not getting the right answer
OpenStudy (anonymous):
4
OpenStudy (anonymous):
What are you getting tell me first...
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OpenStudy (anonymous):
Its not 4...
You are missing something.
OpenStudy (anonymous):
\[\sqrt{3} \times \sqrt{3} = ??\]
OpenStudy (anonymous):
2 times 2=4
root3 times root 3= 3
4 times 3 =12
12 divide3 =4
OpenStudy (anonymous):
12 divided by 3 ???
Are you sure in denominator it is 3 ??
OpenStudy (anonymous):
im not too good with my unit circle
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OpenStudy (anonymous):
Dear, what will you get when you will square 3 ??
OpenStudy (anonymous):
9
OpenStudy (anonymous):
Check the colored things here :
\[\frac{2 \sqrt{3}}{\color{red}{3}} \times \frac{2 \sqrt{3}}{\color{red}{3}} = ??\]
OpenStudy (anonymous):
9
OpenStudy (anonymous):
Yes it is 12 divided by 9 and not 3..
So what will you get now ??
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OpenStudy (anonymous):
ohhhhhh
OpenStudy (anonymous):
4/3
OpenStudy (anonymous):
i was thinking addition
OpenStudy (anonymous):
my mistake...srry if i took up yhur time
OpenStudy (anonymous):
It is okay but be careful from next time...
These are called "Silly Mistakes..."
Ok, now concentrate more on new problems...
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OpenStudy (anonymous):
It is okay..
OpenStudy (anonymous):
thanks a lot :)))