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OpenStudy (anonymous):
hi
13 years ago
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OpenStudy (anonymous):
|dw:1352973817725:dw|
13 years ago
OpenStudy (anonymous):
A person of 60kg is on a water slide 20m in length. she is accelerated down the slide due to gravity. if the coefficient of friction between her and the slide is 0.15, find her acceleration when she is on the slide
13 years ago
OpenStudy (anonymous):
Find her velocity at the end of the slide, so at the 20m before the 2m board thing
13 years ago
OpenStudy (anonymous):
find her acceleration when she is on the 2m board
13 years ago
OpenStudy (anonymous):
\[ma=mg \sin \theta-f_r\]
\[ma=mg-mg \cos \theta \mu\]
\[a=g \sin \theta-g \cos \theta \mu\]
13 years ago
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OpenStudy (anonymous):
2nd equation has sin theta
13 years ago
OpenStudy (anonymous):
does the ? give height or angle
13 years ago
OpenStudy (anonymous):
\[v^2=2(g)(20)\]
13 years ago
OpenStudy (anonymous):
hm? so assume u=0 at start?
13 years ago
OpenStudy (anonymous):
yes othewise its not easy,what about the angle
13 years ago
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OpenStudy (anonymous):
the slide makes 60 degree with vertical
13 years ago
OpenStudy (anonymous):
hm quetion.. when the object travels the whole of the 20m down the slide and goes unto the flat 2m board.. what happ[ens?
13 years ago
OpenStudy (anonymous):
what is the net force when its on the flat board.. and how does affect its velocity
13 years ago
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