hi
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A person of 60kg is on a water slide 20m in length. she is accelerated down the slide due to gravity. if the coefficient of friction between her and the slide is 0.15, find her acceleration when she is on the slide
Find her velocity at the end of the slide, so at the 20m before the 2m board thing
find her acceleration when she is on the 2m board
\[ma=mg \sin \theta-f_r\] \[ma=mg-mg \cos \theta \mu\] \[a=g \sin \theta-g \cos \theta \mu\]
2nd equation has sin theta
does the ? give height or angle
\[v^2=2(g)(20)\]
hm? so assume u=0 at start?
yes othewise its not easy,what about the angle
the slide makes 60 degree with vertical
hm quetion.. when the object travels the whole of the 20m down the slide and goes unto the flat 2m board.. what happ[ens?
what is the net force when its on the flat board.. and how does affect its velocity
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