Question

Please help me! h^2+4=2h solve for h

Answer 1

\[h^2-2h+4=0\] you can use the quadratic formula, but it is easier to complete the square for this one

Answer 2

h=-2 i think

Answer 3

yes, but how to solve :)

Answer 4

\[h^2-2h+4=0\]\[h^2-2h=-4\]\[(h-1)^2=-4+1=-3\]\[h-1=\pm\sqrt{-3}=\pm\sqrt{3i}\]\[h=1\pm\sqrt{3}i\]

Answer 5

D < 0
the roots not real

Answer 6

solutions are complex numbers so if you are working with real numbers you would say "no solution" but if you allow complex solutions the answer and method is above

Answer 7

is 1 necessary infront of +/_square root of 3 i
?

Answer 8

you can write \(\sqrt{3}i+1\) or \(-\sqrt{3}i+1\) if you like but standard form of a complex number is \(a+bi\)

Answer 9

you put the real part first and the "imaginary part" second, so yes you should probably write \(1+\sqrt{3}i\) and \(1-\sqrt{3}i\)

Answer 10

Thank you so much! I really appreciate that!

Answer 11

yw

Answer 12

that satellite person sounds right