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Mathematics 7 Online
OpenStudy (hba):

The range of the function, y=f(x)=|x+2|+3 is A) y>=2 B)y<=-3 C)y>=3 D)y<=3

OpenStudy (hba):

@hartnn

OpenStudy (anonymous):

\[[3,\infty)\]

OpenStudy (anonymous):

C)y>=3

OpenStudy (hba):

Please read the CoC

OpenStudy (hba):

@Godsgirl Please help......

OpenStudy (hba):

@rajathsbhat ?

OpenStudy (hba):

@waterineyes yes ?

OpenStudy (hba):

@Yahoo! Can you tell me how to do it ?

OpenStudy (hba):

@waterineyes Please help ?

OpenStudy (anonymous):

Actually, I don't know how to solve when || comes...

OpenStudy (hba):

So @Yahoo! Can help here ...

OpenStudy (anonymous):

@hba wat do u knw abt modulus

OpenStudy (hba):

I know that Any thing inside the modulus cannot be negative :)

OpenStudy (anonymous):

So the least value of modulus is 0 right

OpenStudy (hba):

Right.

OpenStudy (hba):

So @Yahoo! What next ?

OpenStudy (anonymous):

So wat is the least value here |x+2|+3

OpenStudy (anonymous):

i mean the least value of |x+2|+3

OpenStudy (hba):

3 ?

OpenStudy (anonymous):

Yup....)

OpenStudy (anonymous):

and max is infinity.....

OpenStudy (anonymous):

so which option suits this

OpenStudy (hba):

So C Is the Answer :D

OpenStudy (hba):

@Yahoo! Right ?

OpenStudy (anonymous):

Yes

OpenStudy (hba):

Thanks alot.

OpenStudy (anonymous):

Welcome...brother

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