For number 2, am I doing this correct?
J^b = [Ad(g4g3g2)^-1 * {0;0;1} , Ad(g4g3)^-1*{0;0;1} , Ad(g4)^-1 * {0;0;1}]

J^b = [ (g4g3g2)^-1 * {0;0;1} * g4g3g2 , (g4g3)^-1 *{0;0;1} * g4g3 , g4^-1 * {0;0;1} * g4]

Question

For number 2, am I doing this correct? 
J^b = [Ad(g4g3g2)^-1 * {0;0;1} , Ad(g4g3)^-1*{0;0;1} , Ad(g4)^-1 * {0;0;1}]

J^b = [ (g4g3g2)^-1 * {0;0;1} * g4g3g2 , (g4g3)^-1 *{0;0;1} * g4g3 , g4^-1 * {0;0;1} * g4]

anonymous · Answer

The first part looks right but the second part does not. At the end of the homework there is a formula for the matrix form of the adjoint. you need to multiply that by the [0;0;1]s and THEN invert

anonymous · Answer

I thought that was what I did.  

For example: I multiplied (g4g3g2)^-1 * {0;0;1} * g4g3g2

g4g3g2 is the inverser of (g4g3g2)^-1

anonymous · Answer

O nevermind, I think I understand now.  I need to multiply J*d for (g4g3g2), right?

anonymous · Answer

$$Ad_{h^{-1}}(g) \neq (Ad_h(g))^{-1}$$

anonymous · Answer

You want to do the latter

anonymous · Answer

How would I calculate Js?  Would it be: Js = Ad(ge) * Jb ?

anonymous · Answer

Yep

anonymous · Answer

Does Ad(ge) = [Ad(g4g3g2g1)^-1*{0;0;1} * (g4g3g2g1)] ?

anonymous · Answer

I assume you're referring to the 2D case. The formula for the matrix form of the adjoint is given at the end of the homework.

jaynator495 · Answer

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