Question

-Question related to functions-

Answer 1

The domain of \[f(x)=\frac{ \sqrt{1-2x} }{ \sqrt{4x-1} }\]is given by interval

A)(0.25,0.5)
B)(0.25,0.5]
C)[0.25,0.5)
D)[0.25,0.5]

Answer 2

@satellite73 @surdawi Please Help me Soon!

Answer 3

What about other viewers. They should ignore your question?

Answer 4

@waterineyes Help please !

Answer 5

@chaguanas I never said that.

Answer 6

Denominator should not be 0..

Answer 7

\[\sqrt{4x-1} \ne 0\]

Find x from here...

Answer 8

@waterineyes \[x \neq0.25\]

Answer 9

@waterineyes What next ?

Answer 10

So, now C and D option get cancel..

A and B left as options...

Answer 11

Yeah so how do i know which one is the answer ?

Answer 12

Also \(4x-1 \ge 0\)

So : \(x \ge 0.25\)

But it should not be equal so : \(x > 0.25\)

Answer 13

I got this ^

Answer 14

Because term inside square root must not be negative..

It must be positive:

Similarly:

\[1-2x \ge 0 \implies 2x \le 1 \implies x \le 0.5\]

Answer 15

So :

What should be the answer can you tell??

Answer 16

SO A ?

Answer 17

Its A its A Final Answer :D @waterineyes

Answer 18

A or B??

Answer 19

A

Answer 20

Open bracket means the number is excluded and closed bracket means number should be included..
Here 0.5 is to be included and 0.25 should be excluded..

Now tell me again carefully..

Answer 21

Then B is the answer.Thanks Alot. I got it

Answer 22

Right...

You are welcome dear...