Question

Question about functions :

Answer 1

whats the question?

Answer 2

Which of the following expresses the domain of \[g(x)=\frac{ 3 }{ (x-2)(x+3) }\]

A)\[\left\{ x:x \neq 0 \right\}\]
B)\[\left\{ x:x \neq 2 \right\}\]
C)\[\left\{ x:x \neq -3 \right\}\]

Answer 3

@rajathsbhat

Answer 4

@waterineyes ?

Answer 5

Firstly, denominator must not be 0..

Answer 6

\[(x-2)(x+3) \ne 0\]

Find x..

Answer 7

So x=2,x=-3

Answer 8

This will have two correct choices...

Not equal to man not equal to..

\(x \ne 2\) and \(x \ne -3\)

Answer 9

Yeah right ,What next @waterineyes

Answer 10

so b and c cannot be the answer :)

Answer 11

Cannot??

Why??

Answer 12

I mean can be the answer.

Answer 13

Yes but both...

Answer 14

{x:x is not equal to 2 and x:x is not equal to 3} got it thanks :)