Identify the correct slope and y intercept of the equation 6x – 3y = 12 and equation of the line passing through the point (–4, –2) and perpendicular to y = –x + 6 Thank you!
@Lotsohelpneeded first thing u must know is how to find a slope of line can u find?????????
I know how but it's hard for me because I have dyslexia
1) Identify the correct slope and y intercept of the equation 6x – 3y = 12. Slope-Intercept form is: y = mx + b m is slope b is y-intercept SO, change it into Slope-Intercept form.~ 6x – 3y = 12 Subtract 6x from both sides. -3y = -6x + 12 Divide both sides by -3. y = 2x - 4 y = 2x - 4 Slope is 2 Y-intercept is -4
Thanks jazy!
Just one lest question? Please?
*last
You're welcome! I have to go now but maybe @Aperogalics can help you with the 2nd one. Oh and welcome to OpenStudy!
Write the equation of the line in slope-intercept form with a slope of –6 and a y-intercept of 9
Thanks again
Remember Slope-Intercept form is: y = mx + b m is slope b is y-intercept And plug in the values.(: y = -6x + 9
@Lotsohelpneeded y=mx+c is the slope-intercept form that's not fair @jazy ...lol:)
But wait can I still have the answer to the second problem I originally needed help with
Jazy?
Okay I ended up not leaving! I'll help with the original one.
Thanks
The equation of the line passing through the point (–4, –2) and perpendicular to y = –x + 6 The slope of a perpendicular line is opposite reciprocal. So if our given line has a slope of -1 or -1/1, the new line will have a slope of 1/1 or just 1. So you have: Slope of 1 Point (-4, -2) Use Point-Slope form. y - y1 = m(x - x1) y - (-2) = 1(x - (-2)) Two negatives (-) equal to a Positive(+) y + 2 = 1(x + 2) You need Slope-Intercept form. So, distribute and solve for y. y + 2 = 1(x + 2) y + 2 = x + 2 Subtract 2 from both sides. y = x + 0 Or y = x
Thanks jazy!
Welcome! (: And now I really do have to go. lol
But I don;t have that on the answers
they are only y=-x+6 y=x-6 y=-x-2 y=x+2
nvm
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