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Algebra 8 Online
OpenStudy (anonymous):

Can some one please help me with some factoring problems?

OpenStudy (anonymous):

\[x^{2}-121\]

OpenStudy (poopsiedoodle):

(x-11)(x+11)

OpenStudy (anonymous):

So if I was to do a problem like.. \[4x^{2}-25y^{2}\] It's what numbers add up to 25 & equal 4?

OpenStudy (poopsiedoodle):

kind. it would be the 2 xs multiplying to 4x^2 and the 2 ys multiplying to 25y^2.

OpenStudy (poopsiedoodle):

kinda*

OpenStudy (anonymous):

So I multiply both sides by 2?

OpenStudy (poopsiedoodle):

what? o.o

OpenStudy (poopsiedoodle):

the factors are (2x-5y)(2x+5y) you multiply them by each other.

OpenStudy (anonymous):

Wait so that's the answer? or you have to multiply those to get the answer?

OpenStudy (poopsiedoodle):

no, those ARE the answer. In factoring problems, you are given the answer and you have to find the original problem.

OpenStudy (anonymous):

Okay how about \[4y^{2}-1?\]

OpenStudy (poopsiedoodle):

(2y-1)(2y+1) This is called the difference of squares. If both terms can be square rooted, just put the root of the one with the variable+the root of the number without the variable, then the same but with a - instead of a +, or do it the other way around.

OpenStudy (anonymous):

Okay I see.. so if \[100y^{2}-a ^{2}\] it would be (10y-a) (10y+a)?

OpenStudy (poopsiedoodle):

yesh

OpenStudy (poopsiedoodle):

good job :p

OpenStudy (anonymous):

Thanks! :D Now this next problem I don't understand at all. It's \[36a ^{2}b ^{2}-x ^{2}y ^{2}\]

OpenStudy (poopsiedoodle):

(6ab-xy)(6ab+xy)

OpenStudy (anonymous):

Oh I see, so what if there's another number like.. \[16m ^{2}n ^{2}-9x ^{2}y ^{2} \] ?

OpenStudy (poopsiedoodle):

(╯>_<)╯=====┻━┻

OpenStudy (poopsiedoodle):

(4mn-3xy)(4mn+3xy)

OpenStudy (anonymous):

Lol how about \[36x ^{6}-25y ^{8}\]?

OpenStudy (poopsiedoodle):

(6x^3-5y^4)(6x^3+5y^4)

OpenStudy (anonymous):

What does ^ mean?

OpenStudy (poopsiedoodle):

that's (number)to the (number)th power ie, the 3 in 6x^3 means that the 6x is cubed.

OpenStudy (anonymous):

so \[1-x ^{2}\] would be (x-1) (x+1)

OpenStudy (poopsiedoodle):

(1-x)(1+x)*

OpenStudy (anonymous):

oh okay how about \[m ^{2}n ^{2}-121\]

OpenStudy (poopsiedoodle):

(mn+11)(mn-11)

OpenStudy (anonymous):

Thanks so much, studying for a test! Thanks alot I understand you more than my own teacher.

OpenStudy (poopsiedoodle):

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