Can some one please help me with some factoring problems?
\[x^{2}-121\]
(x-11)(x+11)
So if I was to do a problem like.. \[4x^{2}-25y^{2}\] It's what numbers add up to 25 & equal 4?
kind. it would be the 2 xs multiplying to 4x^2 and the 2 ys multiplying to 25y^2.
kinda*
So I multiply both sides by 2?
what? o.o
the factors are (2x-5y)(2x+5y) you multiply them by each other.
Wait so that's the answer? or you have to multiply those to get the answer?
no, those ARE the answer. In factoring problems, you are given the answer and you have to find the original problem.
Okay how about \[4y^{2}-1?\]
(2y-1)(2y+1) This is called the difference of squares. If both terms can be square rooted, just put the root of the one with the variable+the root of the number without the variable, then the same but with a - instead of a +, or do it the other way around.
Okay I see.. so if \[100y^{2}-a ^{2}\] it would be (10y-a) (10y+a)?
yesh
good job :p
Thanks! :D Now this next problem I don't understand at all. It's \[36a ^{2}b ^{2}-x ^{2}y ^{2}\]
(6ab-xy)(6ab+xy)
Oh I see, so what if there's another number like.. \[16m ^{2}n ^{2}-9x ^{2}y ^{2} \] ?
(╯>_<)╯=====┻━┻
(4mn-3xy)(4mn+3xy)
Lol how about \[36x ^{6}-25y ^{8}\]?
(6x^3-5y^4)(6x^3+5y^4)
What does ^ mean?
that's (number)to the (number)th power ie, the 3 in 6x^3 means that the 6x is cubed.
so \[1-x ^{2}\] would be (x-1) (x+1)
(1-x)(1+x)*
oh okay how about \[m ^{2}n ^{2}-121\]
(mn+11)(mn-11)
Thanks so much, studying for a test! Thanks alot I understand you more than my own teacher.
♥
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