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Physics 20 Online
OpenStudy (anonymous):

I have a test tomorrow and i cant figure out how to do this please help! A scared kangaroo once cleared a fence that was 2.44m high. If the Horizontal component of the kangaroo’s velocity was 4.80 m/s, find the angle with respect to the ground at which the kangaroo leaped.

OpenStudy (anonymous):

I'm giving it a try....it might be wrong but give me a sec to give it a try

OpenStudy (anonymous):

thank you so much

OpenStudy (anonymous):

Do you have the solution? so i can check my solution and see if they match up

OpenStudy (anonymous):

yes i got 55.3 degrees

OpenStudy (anonymous):

not sure if thats right

OpenStudy (anonymous):

Oh i meant like do you have the actual answer Because i have an answer of 26.95 approx as the angle

OpenStudy (anonymous):

Since i treated I used the pythagorean theorem to try and figure it out, but again Im not sure if its right

OpenStudy (anonymous):

yea the angle i got was 55.3

OpenStudy (anonymous):

well you cant use the pathagreom theorem because you're looking for an angle. you can only use pythagream when looking for the lengths of the sides.

OpenStudy (anonymous):

well yeah but if we treat the fence as the other leg of the triangle then we can use it to find the hypoteneus which would give us the velocity at which he took off and then once we have that we can find the angle

OpenStudy (anonymous):

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